Problem Statement

Given a linked list, swap every two adjacent nodes and return its head. You must solve the problem without modifying the values in the list's nodes (i.e., only nodes themselves may be changed.)

Example 1:

Input: head = [1,2,3,4]
Output: [2,1,4,3]

Example 2:

Input: head = []
Output: []

Example 3:

Input: head = [1]
Output: [1]

Constraints:

• The number of nodes in the list is in the range [0, 100].
• 0 <= Node.val <= 100

Problem Link

Swap Nodes in Pairs - LeetCode

Code

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode() : val(0), next(nullptr) {}
 *     ListNode(int x) : val(x), next(nullptr) {}
 *     ListNode(int x, ListNode *next) : val(x), next(next) {}
 * };
 */
class Solution {
public:
    ListNode* swapPairs(ListNode* head) {
        
        if(!head||!head->next)
            return head;
        
        if(!head->next->next)
        {
            ListNode *temp = head;
            head = head->next;
            head->next = temp;
            temp->next = NULL;
            return head;
            
        }
        
        ListNode *curr = head,*nhead = head->next;
        
        while(curr)
        {
            
            ListNode *currn = curr->next;
            if(!currn)
                break;
            ListNode *temp = currn->next;
            currn->next = curr;
            if(temp)
            curr->next = temp->next ? temp->next : temp;
            else 
            curr->next = NULL;
            curr = temp;
            
        }
        
        return nhead;
        
        
    }
};