Given the head of a linked list, rotate the list to the right by k places.
Example 1:

Input: head = [1,2,3,4,5], k = 2
Output: [4,5,1,2,3]
Example 2:

Input: head = [0,1,2], k = 4
Output: [2,0,1]
Constraints:
[0, 500].100 <= Node.val <= 1000 <= k <= 2 * 109/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
class Solution {
public:
ListNode* rotateRight(ListNode* head, int k) {
if(head == NULL || head->next == NULL||k==0) return head;
ListNode* node = head;
int size =1;
while(node->next != NULL)
{
size++;
node = node->next;
}
//loop the list
node->next=head;
//handle the case of k>size
k = k%size;
//find the node to break the loop at
while(--size >= k)
{
node=node->next;
}
ListNode* first = node->next;
node->next=NULL;
return first;
}
};