You are given an array of k linked-lists lists, each linked-list is sorted in ascending order.
Merge all the linked-lists into one sorted linked-list and return it.
Example 1:
Input: lists = [[1,4,5],[1,3,4],[2,6]]
Output: [1,1,2,3,4,4,5,6]
Explanation: The linked-lists are:
[
1->4->5,
1->3->4,
2->6
]
merging them into one sorted list:
1->1->2->3->4->4->5->6
Example 2:
Input: lists = []
Output: []
Example 3:
Input: lists = [[]]
Output: []
Constraints:
k == lists.length0 <= k <= 10^40 <= lists[i].length <= 50010^4 <= lists[i][j] <= 10^4lists[i] is sorted in ascending order.lists[i].length won't exceed 10^4.Merge k Sorted Lists - LeetCode
/**
* Definition for singly-linked list.
* struct ListNode {
* int val;
* ListNode *next;
* ListNode() : val(0), next(nullptr) {}
* ListNode(int x) : val(x), next(nullptr) {}
* ListNode(int x, ListNode *next) : val(x), next(next) {}
* };
*/
#include<iterator>
class Solution {
public:
ListNode* mergeKLists(vector<ListNode*>& lists) {
multimap<int,ListNode*> m;
for(auto list:lists)
{
while(list)
{
m.insert({list->val,list}) ;
list = list->next;
}
}
ListNode *temp = new ListNode();
ListNode *head = temp;
for(auto itr:m)
{
temp->next = itr.second;
temp = temp->next;
}
return head->next;
}
};