Given n non-negative integers a1, a2, ..., an , where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of the line i is at (i, ai) and (i, 0). Find two lines, which, together with the x-axis forms a container, such that the container contains the most water.
Notice that you may not slant the container.
Example 1:

Input: height = [1,8,6,2,5,4,8,3,7]
Output: 49
Explanation: The above vertical lines are represented by array [1,8,6,2,5,4,8,3,7]. In this case, the max area of water (blue section) the container can contain is 49.
Example 2:
Input: height = [1,1]
Output: 1
Example 3:
Input: height = [4,3,2,1,4]
Output: 16
Example 4:
Input: height = [1,2,1]
Output: 2
Constraints:
n == height.length2 <= n <= 1050 <= height[i] <= 104Container With Most Water - LeetCode
class Solution {
public:
int maxArea(vector<int>& height) {
int n = height.size();
int i = 0, j = n-1;
int maxcap = 0;
while(i<=j)
{
int cap = min(height[i],height[j]) * (j-i);
maxcap = max(maxcap,cap);
if(height[i]<height[j])
i++;
else
j--;
}
return maxcap;
}
};