Given two binary strings a and b, return their sum as a binary string.
Example 1:
Input: a = "11", b = "1"
Output: "100"
Example 2:
Input: a = "1010", b = "1011"
Output: "10101"
Constraints:
1 <= a.length, b.length <= 104a and b consist only of '0' or '1' characters.class Solution {
public:
string addBinary(string a, string b) {
if(a=="0")
return b;
if(b=="0")
return a;
int m = a.size();
int n = b.size();
int carry = 0;
int i = m-1;
int j = n-1;
string res = "";
while(carry||i>=0||j>=0)
{
int num1 = i>=0 ? a[i]-'0' : 0;
int num2 = j>=0 ? b[j] - '0' : 0;
int sum = num1+num2+carry;
int digit = sum%2;
res+=to_string(digit);
carry = sum/2;
i--;
j--;
}
reverse(res.begin(),res.end());
return res;
}
};